Approximating ez with Pn(z) = (1 + z/n)n

n = 5

Figure 1. n = 5

n = 1000

Figure 2. n = 103

n = 10000

Figure 3. n = 104

e to z power

Figure 4. ez

This sequence of images is an attempt to reproduce Figure [19], p. 81 of Needham by applying the function Pn(z) = (1 + z/n)n to see how it compares with ez. A good approximation of ez requires a large n.

Last Modified, August 7, 2014, Gary B. Palmer